j^2-10j+21=0

Solution for j^2-10j+21=0 equation:

Simplifying
j2 + -10j + 21 = 0

Reorder the terms:
21 + -10j + j2 = 0

Solving
21 + -10j + j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(3 + -1j)(7 + -1j) = 0

Subproblem 1
Set the factor '(3 + -1j)' equal to zero and attempt to solve:

Simplifying
3 + -1j = 0

Solving
3 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1j = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1j = 0 + -3
-1j = 0 + -3

Combine like terms: 0 + -3 = -3
-1j = -3

Divide each side by '-1'.
j = 3

Simplifying
j = 3
Subproblem 2
Set the factor '(7 + -1j)' equal to zero and attempt to solve:

Simplifying
7 + -1j = 0

Solving
7 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + -1j = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -1j = 0 + -7
-1j = 0 + -7

Combine like terms: 0 + -7 = -7
-1j = -7

Divide each side by '-1'.
j = 7

Simplifying
j = 7
Solution
j = {3, 7}